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From: | "Tonu Aas" <tonu AT ids DOT ee> |
Newsgroups: | comp.os.msdos.djgpp |
References: | <3a30b1a8$0$24264 AT diablo DOT uninet DOT ee> <006101c06103$dc9dd020$aa4d57cb AT spunky> |
Subject: | Re: Help! function typedef |
Date: | Mon, 11 Dec 2000 15:12:43 +0200 |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
> typedef int MY_FUNC_TYPE; > > MY_FUNC_TYPE func(void) > { > return 0; > } > > But it looks as if you were looking for a pointer to a function, in which > case you could do this: ... NO NO NO. I wrote: typedef int (MY_FUNC_TYPE)(void); MY_FUNC func { return 0; } This means that I want to declare just function type. And then I can do: MY_FUNC func1 { return 1; } MY_FUNC func2 { return 2; } MY_FUNC func3 { return 3; } ... and struct blablabla { MY_FUNC *handler1; MY_FUNC *handler2; }; In BC 5.02 its o.k., but in DJGPP I cant declare MY_FUNC func { return 0; } Error: syntax error before `{' But: struct blablabla { MY_FUNC *handler1; MY_FUNC *handler2; }; compiles fine !!! Help somebody help! Tõnu.
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