From: "Tonu Aas" <tonu AT ids DOT ee>
Newsgroups: comp.os.msdos.djgpp
References: <3a30b1a8$0$24264 AT diablo DOT uninet DOT ee> <006101c06103$dc9dd020$aa4d57cb AT spunky>
Subject: Re: Help! function typedef
Date: Mon, 11 Dec 2000 15:12:43 +0200
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To: djgpp AT delorie DOT com
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> typedef int MY_FUNC_TYPE;
>
> MY_FUNC_TYPE func(void)
> {
>     return 0;
> }
>
> But it looks as if you were looking for a pointer to a function, in which
> case you could do this: ...

NO NO NO. I wrote:
typedef int (MY_FUNC_TYPE)(void);

MY_FUNC func
 {
  return 0;
 }

This means that I want to declare just function type. And then I can do:
MY_FUNC func1 {  return 1; }
MY_FUNC func2 {  return 2; }
MY_FUNC func3 {  return 3; } ...

and

struct blablabla
  {
   MY_FUNC     *handler1;
   MY_FUNC     *handler2;
  };

In BC 5.02 its o.k., but in DJGPP  I cant declare
MY_FUNC func
 {
  return 0;
 }
Error: syntax error before `{'

But:
struct blablabla
  {
   MY_FUNC     *handler1;
   MY_FUNC     *handler2;
  };
compiles fine !!!

Help somebody help!

Tõnu.