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| From: | "mike friedrichs" <mike_fr1 AT txucom DOT net> |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: exponment |
| Date: | Sun, 4 Feb 2001 14:29:41 -0600 |
| Organization: | LCC Internet |
| Lines: | 41 |
| Message-ID: | <95keco$mni@atlas.lcc.net> |
| References: | <Dbif6.155$dB3 DOT 33715 AT sapphire DOT mtt DOT net> |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
Drake,
let z = x^y
log(z) = y * log(x)
z = exp(y * log(x))
mike friedrichs
"Drake matthews" <cyberdrake AT icrazy DOT com> wrote in message
news:Dbif6.155$dB3 DOT 33715 AT sapphire DOT mtt DOT net...
> #include <iostream.h>
> #include <conio.h>
>
>
> int main()
> {
> clrscr ();
>
> int intpow;
> int x, int y;
>
>
>
> cout << "This program will compute any base value raised to an exponent
> value" << endl;
>
> cout << "Enter a base value:" << endl;
> cin >> x;
> cout >> "Enter an exponment value:" << endl;
> cin >> y;
> intpow=exp((log(y)*x);
> { if (y == 0) return 1; return x * intpow (x, y - 1); }
>
>
> I'm have trouble writing this program could someone help me.
>
>
>
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