From: "mike friedrichs" Newsgroups: comp.os.msdos.djgpp Subject: Re: exponment Date: Sun, 4 Feb 2001 14:29:41 -0600 Organization: LCC Internet Lines: 41 Message-ID: <95keco$mni@atlas.lcc.net> References: NNTP-Posting-Host: 209.34.2.4 X-Newsreader: Microsoft Outlook Express 5.50.4522.1200 X-MimeOLE: Produced By Microsoft MimeOLE V5.50.4522.1200 To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com Drake, let z = x^y log(z) = y * log(x) z = exp(y * log(x)) mike friedrichs "Drake matthews" wrote in message news:Dbif6.155$dB3 DOT 33715 AT sapphire DOT mtt DOT net... > #include > #include > > > int main() > { > clrscr (); > > int intpow; > int x, int y; > > > > cout << "This program will compute any base value raised to an exponent > value" << endl; > > cout << "Enter a base value:" << endl; > cin >> x; > cout >> "Enter an exponment value:" << endl; > cin >> y; > intpow=exp((log(y)*x); > { if (y == 0) return 1; return x * intpow (x, y - 1); } > > > I'm have trouble writing this program could someone help me. > > >