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| From: | wemccaug AT prairienet DOT org (Wendy E. McCaughrin) |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: "mod" in Pascal equivalent to %?? |
| References: | <7uamr7$ot8$1 AT ctb-nnrp2 DOT saix DOT net> |
| Lines: | 34 |
| Message-ID: | <Lb7O3.99$Ak5.42@firefly> |
| Date: | Sat, 16 Oct 1999 22:42:51 GMT |
| NNTP-Posting-Host: | 192.17.3.4 |
| X-Complaints-To: | newsmgr AT prairienet DOT org |
| X-Trace: | firefly 940113771 192.17.3.4 (Sat, 16 Oct 1999 17:42:51 CDT) |
| NNTP-Posting-Date: | Sat, 16 Oct 1999 17:42:51 CDT |
| Organization: | Prairienet -- Your Community Network for East Central Illinois |
| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
In a previous article, rylan AT intekom DOT com ("Stefan Viljoen") says:
>Hi All,
>
>Am I correct in the assumption that the DJGPP (or C?) equivalent for the
>"mod" that you find in say, this line of Pascal
>
>total := whatever mod sum;
>
>is
>
>total = whatever % sum;
>
>Is this correct? Is "%" equivalent to "mod" (modulo?) If not, what is
>equivalent?
>
>Fanx!
>
Yes, both `mod' and % should return the remainder upon integer division
of whatever by sum. You might want to check what happens when either
dividend or divisor is negative, and what happens when sum = 0 in both
cases.
>--
>This message courtesy of
>RylanNet rylan AT intekom DOT co DOT za
>http://home.intekom.com/rylan/
>--
>StarWars for ever!.
>
>
>
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