From: wemccaug AT prairienet DOT org (Wendy E. McCaughrin) Newsgroups: comp.os.msdos.djgpp Subject: Re: "mod" in Pascal equivalent to %?? References: <7uamr7$ot8$1 AT ctb-nnrp2 DOT saix DOT net> Lines: 34 Message-ID: Date: Sat, 16 Oct 1999 22:42:51 GMT NNTP-Posting-Host: 192.17.3.4 X-Complaints-To: newsmgr AT prairienet DOT org X-Trace: firefly 940113771 192.17.3.4 (Sat, 16 Oct 1999 17:42:51 CDT) NNTP-Posting-Date: Sat, 16 Oct 1999 17:42:51 CDT Organization: Prairienet -- Your Community Network for East Central Illinois To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com In a previous article, rylan AT intekom DOT com ("Stefan Viljoen") says: >Hi All, > >Am I correct in the assumption that the DJGPP (or C?) equivalent for the >"mod" that you find in say, this line of Pascal > >total := whatever mod sum; > >is > >total = whatever % sum; > >Is this correct? Is "%" equivalent to "mod" (modulo?) If not, what is >equivalent? > >Fanx! > Yes, both `mod' and % should return the remainder upon integer division of whatever by sum. You might want to check what happens when either dividend or divisor is negative, and what happens when sum = 0 in both cases. >-- >This message courtesy of >RylanNet rylan AT intekom DOT co DOT za >http://home.intekom.com/rylan/ >-- >StarWars for ever!. > > >