From:	the stress tensor <entropic AT mpx DOT com DOT au>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: How do I pass * (astrix) over argv ?
Date:	Tue, 21 Sep 1999 14:02:53 +1000
Organization:	Optus Internet
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Message-ID:	<37E7036D.3CD17002@mpx.com.au>
References:	<7s6rjn$gq7$1 AT nnrp1 DOT deja DOT com>
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

hey there,

  the MS-DOS command interpreter translates the wildcards to the actual
arguments.
  you can avoid this by enclosing them in double quotes:

  example:   ls "*.*" will not list everything in yr directory - it will
fail


hope this helps :)
daniel.

hank_heng AT hotmail DOT com wrote:
> 
> Hello,
> 
>   I'm using DJGPP, and I notice that if I do something like this :
> 
>   myprog *.*
> 
>   *.* actually copy all available file name that found in that
> directory and store it in argv[1], argv[2], argv[3] ... and so on...
> 
>   I don't want this to happen, so how do I pass '*.*' over the command
> line and receive '*.*' in argv[1] instead of bunches of file names.
> 
>   Thanks For Reading This And Please Help Me Out.  :)
> 
> -Hank
> 
> Sent via Deja.com http://www.deja.com/
> Share what you know. Learn what you don't.

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