From: the stress tensor Newsgroups: comp.os.msdos.djgpp Subject: Re: How do I pass * (astrix) over argv ? Date: Tue, 21 Sep 1999 14:02:53 +1000 Organization: Optus Internet Lines: 33 Message-ID: <37E7036D.3CD17002@mpx.com.au> References: <7s6rjn$gq7$1 AT nnrp1 DOT deja DOT com> NNTP-Posting-Host: dialup-wdc248249.mpx.com.au Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit X-Trace: news1.mpx.com.au 937886560 1889 198.142.248.249 (21 Sep 1999 04:02:40 GMT) X-Complaints-To: abuse AT mpx DOT com DOT au NNTP-Posting-Date: 21 Sep 1999 04:02:40 GMT X-Mailer: Mozilla 4.5 [en] (Win95; I) X-Accept-Language: en To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com hey there, the MS-DOS command interpreter translates the wildcards to the actual arguments. you can avoid this by enclosing them in double quotes: example: ls "*.*" will not list everything in yr directory - it will fail hope this helps :) daniel. hank_heng AT hotmail DOT com wrote: > > Hello, > > I'm using DJGPP, and I notice that if I do something like this : > > myprog *.* > > *.* actually copy all available file name that found in that > directory and store it in argv[1], argv[2], argv[3] ... and so on... > > I don't want this to happen, so how do I pass '*.*' over the command > line and receive '*.*' in argv[1] instead of bunches of file names. > > Thanks For Reading This And Please Help Me Out. :) > > -Hank > > Sent via Deja.com http://www.deja.com/ > Share what you know. Learn what you don't.