To: opendos AT delorie DOT com
X-Comment-To: "da Silva, Joe" <Joe DOT daSilva AT emailmetering DOT com>
References: <01FD6EC775C6D4119CDF0090273F74A4021FBC AT emwatent02 DOT meters DOT com DOT au>
Message-Id: <2.07b7.5N0Q.G9RUEG@belous.munic.msk.su>
From: "Arkady V.Belousov" <ark AT belous DOT munic DOT msk DOT su>
Date: Tue,  6 Mar 2001 13:27:52 +0300 (MSK)
Organization: Locus
X-Mailer: dMail [Demos Mail for DOS v2.07b7]
Subject: Re: Text file format .ASC ?
Lines: 25
MIME-Version: 1.0
Content-Type: text/plain; charset=koi8-r
Content-Transfer-Encoding: 8bit
Reply-To: opendos AT delorie DOT com

X-Comment-To: da Silva, Joe

Hi!

6-Мар-2001 19:38 Joe DOT daSilva AT emailmetering DOT com (da Silva, Joe) wrote to
"'opendos AT delorie DOT com'" <opendos AT delorie DOT com>:

dJ> Does anyone know how to decypher a text file, with filename
dJ> extension ".ASC", which seems to :

     No. This _absolutely_ depends from encoding scheme, which was used to
generate this file. You should (1) which algorithm was used to encode, (2)
which program do this and/or you should (3) citate small typical part of
those file to let us decide how this file generated if you don't know this
themselves. In any case, (3) or even (2) not neccessarilly allows us to
decode real contents of this file.

dJ> 2. Use some other encoding for characters above *about*
dJ>    96 ($60). For instance, character 109 ($6D) is either the
dJ>    the Roman letter 'u' or the Greek letter "mu", whereas in
dJ>    ASCII, this should be the Roman letter 'm' ...
dJ> The above clues were obtained from the following fragment :
dJ> 2C 20 6D 50 43 34 39 34 43 2C 20         , mPC494C,

     What here give you reason to think about 'm' as "mu" replacement?