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Date: Tue, 14 Jul 2015 14:19:01 +0200 (CEST)
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To: "Mitch Davis (mjd+geda-user AT hackvana DOT com) [via geda-user AT delorie DOT com]" <geda-user AT delorie DOT com>
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From: gedau AT igor2 DOT repo DOT hu
Subject: Re: [geda-user] why I parse sch: gnetlist, writing backends (Back
 annotation)
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On Tue, 14 Jul 2015, Mitch Davis (mjd+geda-user AT hackvana DOT com) [via geda-use=
r AT delorie DOT com] wrote:

>On Sat, Jul 11, 2015 at 7:34 AM, Roland Lutz <rlutz AT hedmen DOT org> wrote:
>      On Fri, 10 Jul 2015, gedau AT igor2 DOT repo DOT hu wrote:
>            So next time I have something similar to solve, I
>            will first ask you for the scheme code and only if
>            that fails I do the dirty sch-parsing awk fewliner.
>
>
>      You could use Xorn.=C2=A0 Since this uses the actual gEDA parsing
>      code, the result is exactly what gEDA would see when reading the
>      file.=C2=A0 Taking the "outputting coords of line segments" task as
>      an example, this would be:
>
>      =C2=A0 =C2=A0 import xorn.storage
>      =C2=A0 =C2=A0 from xorn.geda.read import read
>
>      =C2=A0 =C2=A0 sch =3D read('some-schematic.sch')
>
>      =C2=A0 =C2=A0 for ob in sch.toplevel_objects():
>      =C2=A0 =C2=A0 =C2=A0 =C2=A0 data =3D ob.data()
>      =C2=A0 =C2=A0 =C2=A0 =C2=A0 if isinstance(data, xorn.storage.Line):
>      =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 print 'X1: %d Y1: %d X2: %=
d Y2: %d' % (
>      =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 data.x, data=
=2Ey, data.x + data.width, data.y +
>      data.height)
>
>
>I don't know why everyone is complaining about Scheme.=C2=A0 I can read th=
is just
>fine, the first time I ever saw it.

One of the reasons for that might be that the above code is not in Scheme.

</sarcasm>


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