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From: "Anthony" <akantsel AT integra DOT rmt DOT ru>
Newsgroups: comp.os.msdos.djgpp
Subject: Inline functions question
Date: Fri, 23 Apr 2004 18:08:41 +0400
Organization: Radio-MSU NOC, Moscow State University
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

Hello,

Why does this code

#include <iostream>

class A {
    public:
    void f1();
    inline void f2(const char* str);
};

inline void A::f2(const char *str)
{
    std::cout << "\n __func__ = " << __func__
            << "\n __PRETTY_FUNCTION__ = " << __PRETTY_FUNCTION__
            << "\n Caller = " << str;
}

void A::f1()
{
    std::cout << "\n Now f1() will call f2().";
    f2(__func__);
}

int main()
{
    A a;
    a.f1();
}

produces this:

Now f1() will call f2().
__func__ = f2        <---- I expected f1
__PRETTY_FUNCTION__ = void A::f2(const char*)        <---- I expected
A::f2(...)
Caller = f1

The f2() is supposed to be implanted in f1(), no?
Thanks.
Anthony.