Message-ID: <3AE082F7.B4E9C05@jps.net>
From: Dennis Yelle <dennis51 AT jps DOT net>
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Subject: Printing function pointers
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Date: Fri, 20 Apr 2001 11:41:59 -0700
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I was surprised by the output from this program:
---------------------
#include <iostream>

int junk1() { return 111; }

int junk2() { return 222; }

int main()
{
  if ( junk1 != junk2 ) {
    cout << "different\n";
  }
  cout << junk1 << '\n';
  cout << junk2 << '\n';
  return 0;
}
----------------------

I got this:
----------------
different
1
1
---------------

So, the function pointers are different, but
they both print as 1.  Is this expected, and desired
behavior?  Or is it a bug?

Dennis Yelle
-- 
I am a computer programmer and I am looking for a job.
There is a link to my resume here:  
http://table.jps.net/~vert/