From: "Marp" <marp AT 0 DOT 0 DOT 0 DOT 0>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: BREAKing out of a nested loop
Date: Wed, 2 Aug 2000 23:53:15 -0400
Organization: MindSpring Enterprises
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

See my other post first please. I forgot to say that you could put a =
pptest_w + 1; just before you use break. That would cause the outer loop to
terminate.

"23yrold3yrold" <cbarry AT pangea DOT ca> wrote in message
news:3988bc46_2 AT spamkiller DOT newsfeeds DOT com...
> Hullo. I would like a little help with something. I've written a simple
> collision-detection program, but I need a little clarification with
> something:
>
>
> for(int a = 1; a <= pptest_w; a++){
>    for(int b = 1; b <= pptest_h; b++){
>       pixelcheck = getpixel(pptest_1a, a, b);
>       if(pixelcheck <= 0){
>       }else if(pixelcheck != 0){
>          pixelcheck = getpixel(pptest_2a, a, b);
>          if(pixelcheck <= 0){
>          }else if(pixelcheck != 0){
>             collide = 1;
>             break;
>          }
>       }
>    }
> }
>
> FUNKtion();
>
> I would like to get it to break as soon as a collision is detected and go
> straight to FUNKtion(). Is this enough to bust out of all those nested
> loops? Putting if(collide){break;} latter in that mess would be kind of
> stupid because you're just putting it in another loop, correct? Any help
> will be appreciated. Thank you.
>
>
> Chris
>
>