From: "Shawn" <NRLax27 AT aol DOT com>
Newsgroups: comp.os.msdos.djgpp
References: <82cko6$sfk$1 AT imsp026 DOT netvigator DOT com>
Subject: Re: Why "c" is always zero??
Date: Sun, 5 Dec 1999 03:45:42 -0500
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com


>Can anyone tells me why the value of "c" is always equal to zero??
>How can I correct this?
>Thanks a lot!!

>#include <stdio.h>
>float ftc(n)
>int n;
>{
>float c, f; int i;
> for (i=0;i<=n;i++){
> c=5/9*(f-32);
>        }
>return c;
>}
>main ()
>{
>float c, f=0; int i=0;
>do
>{
>c=ftc(i);
>printf("\t\t F=%.2f \t\t C=%.2f\n",f,c);
>f++;
>i++;
>} while (i<=100);
>}
Jason,

    Have you tried initializing the value of f in your function ftc() to
some value before you start?  A solution might be:

float ftc(int n)
{
    float c, f;
    int i;

    for(f=0, i=0; i<=n, i++)
        c=5/9*(f-32);

    return c;
}

However, some points:

What is the purpose of this function?  This loop doesn't appear to be doing
too much.  You are calculating the same value n times and then returning the
value.

Hope this helps!

-Shawn