From: esox1999 AT my-deja DOT com
Newsgroups: comp.os.msdos.djgpp
Subject: A way to go ring0 with gcc, to deal with virtual addresses ?
Date: Wed, 10 Nov 1999 11:56:44 GMT
Organization: Deja.com - Before you buy.
Lines: 19
Message-ID: <80bmhr$m14$1@nnrp1.deja.com>
NNTP-Posting-Host: 129.234.4.10
X-Article-Creation-Date: Wed Nov 10 11:56:44 1999 GMT
X-Http-User-Agent: Mozilla/4.61 [en] (WinNT; I)
X-Http-Proxy: 1.0 wwwcache.dur.ac.uk:8080 (Squid/2.2.STABLE2), 1.0 x27.deja.com:80 (Squid/1.1.22) for client 129.234.86.47, 129.234.4.10
X-MyDeja-Info: XMYDJUIDesox1999
To: djgpp AT delorie DOT com
DJ-Gateway: from newsgroup comp.os.msdos.djgpp
Reply-To: djgpp AT delorie DOT com

Hi, I try to go ring0 with gcc. I use a pentium
with w95.
I know it is possible to go ring0, I've read an
article which shows the trick :
http://asmjournal.freeservers.com/issues/
apj_1.txt

but it is the intel asm syntax in this article.
I'd like to do the same with the AT&T syntax. Do
anyone know how to do that, and if there is an
exemple somewhere ? Actually, I can't find the
equivalent for the opcodes such as sidt, sldt in
the AT&T syntax.

My aim is to access the physical addresses.


Sent via Deja.com http://www.deja.com/
Before you buy.