From: Martin Ambuhl <mambuhl AT earthlink DOT net>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Convert String to char *
Date: Wed, 03 Nov 1999 12:56:43 -0500
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Nicolas Blais wrote:
> 
> How do I convert a String to a character array *?

#include <_String.h>    // for obsolete libg++ String class
#include <string>       // for standard c++ string class
#include <iostream>

int main(void)
{
    const char *s;
    char hold[256];
    string ansi("This is an ansi C++ string");
    String gpp("This is an obsolete libg++ String");

    s = ansi.c_str();
    strcpy(hold, s);
    cout << "The string `ansi' is at " << (void *)&ansi << "\n"
        << "and prints as \"" << ansi << "\"\n"
        << "The char* s points to " << (void *)s << "\n"
        << "and prints as \"" << s << "\"\n"
        << "The char[] hold is at " << (void *)hold << "\n"
        << "and prints as \"" << hold << "\"\n" << endl;
    
    s = (const char *)gpp;
    strcpy(hold, s);
    cout << "The string `gpp' is at " << (void *)&gpp << "\n"
        << "and prints as \"" << gpp << "\"\n"
        << "The char* s points to " << (void *)s << "\n"
        << "and prints as \"" << s << "\"\n"
        << "The char[] hold is at " << (void *)hold << "\n"
        << "and prints as \"" << hold << "\"" << endl;
    
    return 0;
}


The string `ansi' is at 0xbd5e0
and prints as "This is an ansi C++ string"
The char* s points to 0xbfa9c
and prints as "This is an ansi C++ string"
The char[] hold is at 0xbd600
and prints as "This is an ansi C++ string"

The string `gpp' is at 0xbd5c0
and prints as "This is an obsolete libg++ String"
The char* s points to 0xc0218
and prints as "This is an obsolete libg++ String"
The char[] hold is at 0xbd600
and prints as "This is an obsolete libg++ String"


-- 
Martin Ambuhl	mambuhl AT earthlink DOT net

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