From: ryot AT bigfoot DOT com (George Ryot)
Newsgroups: comp.os.msdos.djgpp
Subject: Re: How to print a control-key on a file?
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Date: Sun, 03 Oct 1999 12:43:02 GMT
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To: djgpp AT delorie DOT com
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> > Open the file in binary mode:
> >
> >         fp = fopen("stuff","wb");
> >         fp = fopen("stuff","rb");
> >
> > By default "r" and "w" open in text mode. In text mode  (char)10=='\n'
> > is translated by DOS compilers to the sequence 13 10 and 13 10 are
> > read back as a single (char)10=='\n'.
> >

> Yeap I tried that one but it just blow me up. I run DJGPP on WinDOSBox.
> I don't know what happened but fprintf,  putc etc.. just won't work.
> 
> Is there a problem with this simple (overdefining) lines?
> 
> FILE *_outfile  =  fopen("test.zzz", "wb");
> fprintf( _outfile, "%1c",  (char)10&0xFF);

Either there is something else wrong with your code, or there is
something wrong with the way you are viewing the output file because
the above should work.

Try this:

/* test.c */
#include <stdio.h>
int main(void) {
    FILE *_outfile  =  fopen("test.zzz", "wb");
    fprintf( _outfile, "%c",  10);
    return(0);
 }

Compile with:

gcc -Wall -W test.c -o test

Run test.exe then do a dir listing.

You should see that the file test.zzz is only one byte in size.

> Do you have hardcoding technique to stripe the 13 in front of  control key

I don't understand what you mean by that.
-- 
george