From: Martin Ambuhl <mambuhl AT earthlink DOT net>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: How do I pass * (astrix) over argv ?
Date: Tue, 21 Sep 1999 03:01:25 -0400
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hank_heng AT hotmail DOT com wrote:
> 
> Hello,
> 
>   I'm using DJGPP, and I notice that if I do something like this :
> 
>   myprog *.*
> 
>   *.* actually copy all available file name that found in that
> directory and store it in argv[1], argv[2], argv[3] ... and so on...
> 
>   I don't want this to happen, so how do I pass '*.*' over the command
> line and receive '*.*' in argv[1] instead of bunches of file names.
> 

#include <stdio.h>

int main(int argc, char *argv[])
{
    printf("argc = %d\n"
            "If argc > 0, argv follows:\n", argc);
    
    while (*argv) 
        printf("%s\n",*argv++);
    return 0;
}



>a '*.*'

argc = 2
If argc > 0, argv follows:
./a.exe
*.*


-- 
Martin Ambuhl	mambuhl AT earthlink DOT net

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