From: hank_heng AT hotmail DOT com Newsgroups: comp.os.msdos.djgpp Subject: How do I pass * (astrix) over argv ? Date: Tue, 21 Sep 1999 02:47:21 GMT Organization: Deja.com - Share what you know. Learn what you don't. Lines: 21 Message-ID: <7s6rjn$gq7$1@nnrp1.deja.com> NNTP-Posting-Host: 161.142.112.8 X-Article-Creation-Date: Tue Sep 21 02:47:21 1999 GMT X-Http-User-Agent: Mozilla/4.0 (compatible; MSIE 4.01; Windows 98) X-Http-Proxy: 1.0 FIREWALL,NetCache AT jrc-cache8: Version 3.3.1P1, 1.0 x35.deja.com:80 (Squid/1.1.22) for client 161.142.112.8 X-MyDeja-Info: XMYDJUIDhank_heng To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com Hello, I'm using DJGPP, and I notice that if I do something like this : myprog *.* *.* actually copy all available file name that found in that directory and store it in argv[1], argv[2], argv[3] ... and so on... I don't want this to happen, so how do I pass '*.*' over the command line and receive '*.*' in argv[1] instead of bunches of file names. Thanks For Reading This And Please Help Me Out. :) -Hank Sent via Deja.com http://www.deja.com/ Share what you know. Learn what you don't.