From: kalum AT mycabin DOT com
Message-ID: <37C6842800155803@mypad.MYPAD.COM> (added by postmaster@mypad.MYPAD.COM)
To: djgpp AT delorie DOT com
Subject: Re: Problem with while-loop
Date: Sun, 5 Sep 99 08:11:14 +0000
X-Mailer: Endymion MailMan Standard Edition v3.0.2
Reply-To: djgpp AT delorie DOT com

> First of all, I'm a beginner in C++ and I hope I am at the right place
> in this newsgroup.
> I bought a book on learning C++ and along with it I got a copy of 
> the GNU-C++ Compiler V. 2.7.2.1 for DOS from DJGPP.
> In the book there was a sample program introducing encapsulated
> while-loops. A turning line (\|/-) should be shown on the screen.
> Now my problem is, the program doesn't seem to do anything !
> It compiles without any problems, but when I execute it, it shows
> nothing on the screen.
> After I finally use  to stop the programm, only the last
> charakter (e.g.: "\") is shown.
> I took the source code right from the CD I got with my book, so there
> can't be any typing errors.
> On the CD there is also an executable program, which runs perfectly !
>  
> Does anybody have a clue what might be the problem ?
> 
> I enclosed the following things :  - my environment variables	 
> environ.lst
> 				   - compiler startup messages	  go32.lst
> 			    	   - the problematic source code  
rotsl.cpp

Kalum AT mycabin DOT com replied,
My friend your attachement looked so distorted, i think it might have been
sent through a word processor wich caused huge distortions like line wrapping
before it was put on the CD. 
It would be a good idea to check the rotsl.cpp example in the book and see whether it
matched the rotsl.cpp wich you attached to your email.
I suggest examining other examples and seeing wether this
is indeed the case.
In C++ a "//" means that it is a comment and the compiler ignores anything on
the sameline after it.
for example  note that in the following line
printf("1"); //printf("2");
the printf("2") will be ignored.
So following the distortions several lines of your code are being commented
out.

//Anyway I rearranged your code so that it looks like this.


#include <stdio.h>                                          
// printf
void main()
{
double cnt; 
while(1)       
	 // Endlosschleife
  {
                 printf ("|");
	 // Zeichen ausgeben
	 cnt = 0.0;    
	 // Z„hlvariable initialisieren
	 while(cnt < 100000.0)
	 // Pause
	 cnt++;
	 printf("\b"); 
	 // Ausgabe-Position 1 Zeichen zur�cksetzen
	 printf ("/");
	 // Zeichen ausgeben
	 cnt = 0.0; 
	 // Z„hlvariable initialisieren
	 while(cnt < 100000.0)
	 // Pause
	 cnt++;
	 printf("\b");
	 // Ausgabe-Position 1 Zeichen zur�cksetzen
	 printf ("-");
	 // Zeichen ausgeben
	 cnt = 0.0;
	 // Z„hlvariable initialisieren
	 while(cnt < 100000.0)
	 // Pause
	 cnt++;
	 printf("\b");   
	 // Ausgabe-Position 1 Zeichen zur�cksetzen
	 printf ("\\"); 
	 // Zeichen ausgeben
	 cnt = 0.0; 
	 // Z„hlvariable initialisieren
	 while(cnt < 100000.0)
	 // Pause
	 cnt++;
	 printf("\b");
	 // Ausgabe-Position 1 Zeichen zur�cksetzen
  }     // Ende while
	
}

I hope this helps.




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