From: "OmniMeta" Newsgroups: comp.os.msdos.djgpp Subject: Need help with class stuff Lines: 72 X-Priority: 3 X-MSMail-Priority: Normal X-Newsreader: Microsoft Outlook Express 5.00.2014.211 X-MimeOLE: Produced By Microsoft MimeOLE V5.00.2014.211 Message-ID: Date: Fri, 16 Jul 1999 17:25:23 -0300 NNTP-Posting-Host: 207.253.161.51 X-Complaints-To: abuse AT videotron DOT net X-Trace: wagner.videotron.net 932160115 207.253.161.51 (Fri, 16 Jul 1999 17:21:55 EDT) NNTP-Posting-Date: Fri, 16 Jul 1999 17:21:55 EDT To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com This program call a class function using a pointer to it. Can someone please tell me why I get the warning : tst.cpp(44) Warning: converting from `void (Test::*)()' to `void (*)()' tst.cpp(45) Warning: converting from `void (Test::*)()' to `void (*)()' Here is the little program : #include // printf #include // clrscr getch class Test { void Print1(); void Print2(); public: void (*Action)(); // my pointer char select(char key); }ClassTest; int main() { clrscr(); printf("Type 1 or 2 : "); fflush(stdout); do{} while( ClassTest.select(getch()) ); ClassTest.Action(); printf("\nPress a key to exit"); fflush(stdout); getch(); return 0; } char Test::select(char key) { switch(key) { // I get the warning at case '1': Action = &Print1; break; // this line case '2': Action = &Print2; break; // And this line default : return 1; } return 0; } void Test::Print1() { printf("\n\nHello !!!\nThis is what Print1 do.\n"); } void Test::Print2() { printf("\n\nHello !!!\nThis is what Print2 do.\n"); }