From: "Robert W. Hazard" Newsgroups: comp.os.msdos.djgpp Subject: Re: Default File Size Blocks in Win95 Date: Wed, 16 Jun 1999 12:27:45 -0400 Organization: Raytheon Company Lines: 22 Message-ID: <3767D081.1FACAA78@res.raytheon.com> References: <3768C593 DOT 1F320E9C AT accord-soft DOT com> NNTP-Posting-Host: neotwk1.msd.ray.com Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit X-Trace: swlmail.msd.ray.com 929550466 25088 138.127.111.24 (16 Jun 1999 16:27:46 GMT) X-Complaints-To: usenet AT swl DOT msd DOT ray DOT com NNTP-Posting-Date: 16 Jun 1999 16:27:46 GMT X-Mailer: Mozilla 4.6 [en] (WinNT; U) X-Accept-Language: en To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com The short answer is: File size / allocation of disk space is DOS / FAT driven which is 16 bit, and blocks are 16k. Use or convert to a FAT32 formatted drive (available under certain win97 installations, and win98), and I think they are allocated on a 4k per block basis. Likewise for an NT machine and the NTFS formatting. Sunil V wrote: > Hi everybody, > > I have observed that when you create a file in Win 95, even if the file > is of size 1 byte it > takes up 16 K Bytes or 32 K Bytes of secondary memory. File size > allocation is always in terms of multiples of this block size. Is there > a way by which the default block size could be changed to something > lower. > > Thanx in advance, > Regards Sunil > > --