From: "Ron Higgins" Newsgroups: comp.os.msdos.djgpp Subject: Newbie Pointers Date: Sun, 14 Mar 1999 19:27:13 -0000 Organization: Customer of Planet Online Lines: 59 Message-ID: <7ch367$frr$1@news4.svr.pol.co.uk> NNTP-Posting-Host: modem-91.amlodipine.dialup.pol.co.uk X-Trace: news4.svr.pol.co.uk 921440263 16251 62.136.50.219 (14 Mar 1999 19:37:43 GMT) NNTP-Posting-Date: 14 Mar 1999 19:37:43 GMT X-Complaints-To: abuse AT theplanet DOT net X-Newsreader: Microsoft Outlook Express 4.72.3110.1 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Reply-To: djgpp AT delorie DOT com The Exercise Define a character array and use "strcpy" to copy a string into it. Print the string out by using a loop with a pointer to print out one character at a time. Initialise the pointer to the first element and use the double plus sign to increment the pointer. Use a seperate integer variable to count the characters to print. b) Modify the program to print out the string backwards by pointing to the end and using a decrementing pointer. After a time getting CRAZY I decided to do it just using arrays and came up with this , main() { static char ar1[16]; char *ptr1; /* this was from my attempt using pointers, ignore */ int count; strcpy(ar1,"This is a string"); for (count=0;count<16;count++) { printf("%c\n",ar1[count]); } for (count=15;count>-1;count--) { printf("%c\n",ar1[count]); } } which would be fine if the exercise didn't mention pointers :( my mind is going along the lines : ptr1=ar1; while (ptr1 !=0(???)) printf("%c\n",ptr1); ptr++; but this list lots of ascii characters b) ptr1=ar1[15] while (ptr1 !=something???) printf("%c\n",ptr); ptr--; I don't know whether I am miles away or close to solving the problem -- L8ter, Ron -- L8ter, Ron