From: happy303 AT hotmail DOT com (happy303)
Newsgroups: comp.os.msdos.djgpp
Subject: Re: question about Rhide
Message-ID: <36801646.3604022@news.videotron.ca>
References: <75on7n$q7o$1 AT fe2 DOT cs DOT interbusiness DOT it>
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Date: Tue, 22 Dec 1998 22:05:15 GMT
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

On Tue, 22 Dec 1998 19:14:54 +0100, "Bonifati" <abonifati AT telsa DOT it>
wrote:

Hmm you don't have to ask permission to try these things ;)
Suppose i have this: int array[10];
I usually put a watch on "array" and things work out well.  Try this
and watch array :)
see ya!

void main(void)
{
 int array[10];
 int cc;
 cc=0;
 while(cc<10)
 {
  array[cc]=cc;   //put a breakpoint here
  cc++;
 }
 cc=0;
}


>I'm an italian student. I have a question about RHIDE. Please answer. Thank
>you !
>
>How can I watch arrays? I now a pointer is equivalent to an array in C,
>but if I want to see an array represented by a pointer variable, let's say
>int *a; of 5 elements, I'm obliged to write (in the "Add to watch list"
>box):
>
>a[0]
>a[1]
>a[2]
>a[3]
>a[4]
>
>Is there a shorter way? (When I define a static array, for example
>int a[5], it is enough writing "a" in the Add to watch list box to watch
>the array)
>
>Antonio Bonifati - Italy
>abonifati AT telsa DOT it  << my e-mail!
>
>
>
>
>
>
>