From: "Böhme Uwe" <uwe AT hof DOT baynet DOT de>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: please help {newbie}
Date: Wed, 29 Jul 1998 12:57:40 +0200
Organization: Bingo (Buergernetz Ingolstadt eV)
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> how do i read a file name to the program in the calling statement i.e.
> "c:\resolve test.txt"
>
> thanks
> heinrich

  If a program is called with command line arguments (or without) you'll
get two parameters passed to your main()

int main(int argc, char *argv[])

The argc argument keep the number of command line arguments (at least 1,
even if no argument is specified),
argv[0] is a pointer to a string wich is holding the path of the exe file
itself (i.e. "c:\resolve.exe").
In your example argc would be 2 and argvc[1] would point to "test.txt".
Additional arguments increase argc and the n'th argument can be read by
argv[ n - 1 ].

Good luck
Uwe