Newsgroups: comp.os.msdos.djgpp Subject: Re: round From: frenchc AT cadvision DOT com (Calvin French) References: <34c3be38 DOT 741112 AT nntpserver DOT swip DOT net> MIME-Version: 1.0 Content-Type: Text/Plain; charset=US-ASCII NNTP-Posting-Host: ts7ip236.cadvision.com Message-ID: <34c3efbc.0@news.cadvision.com> Date: 20 Jan 98 00:28:44 GMT Organization: CADVision Development Corporation (http://www.cadvision.com/) Lines: 30 To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Precedence: bulk >I want to know how to assign a double value to an int. Like this for >example: Sure, use typecasting. This tells the compiler, convert from such-and-such a format to such-and-such, if you can. If it can't it will give you a message more or less (often less, unfortunately) to that effect. >int hej = (PI*sin(34)/43); int hej = (int) ( (float)PI * (float)sin(34) / (float)43 ); OR int hej = int( float( PI ) * float( sin(34) ) / float( 43 ) ); But some of these probably don't need to be in there. But you can put them all just to be safe. This probably is fine (note the 43.0 versus just plain old 43): int hej = (int) (PI * sin(34) / 43.0); >I want the value rounded. Please help me I'm a beginner =). I think that it gets rounded when converted from float, but remember that when just dividing two integers nothing is rounded, or rather, it's always rounded down. - Calvin -s