From: comeau AT panix DOT com (Greg Comeau)
Newsgroups: comp.os.linux.development.apps,comp.os.msdos.djgpp,comp.unix.programmer
Subject: Re: C++ Passing ostreams by reference to methods, problem
Date: 30 May 1997 15:12:17 -0400
Organization: Comeau Computing; http://www.comeaucomputing.com
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References: <01bc6b49$27fce100$1b2443a1 AT pcoec DOT uclm DOT es>
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In article <01bc6b49$27fce100$1b2443a1 AT pcoec DOT uclm DOT es> "Roberto Henríquez Laurent" <shl24634 AT alumnos DOT inf-cr DOT uclm DOT es> writes:
>
>	I'm trying to pass a stream to a method as a by-reference parameter so
>that this method could write info to it, in this way:
>
>	i've got a class which defines one of its methods as this:
>
>	void WriteYourInfo(ofstream &Dest)
>	{
>		Dest << "This is a test";
>	}
>	
>	And I call the method like this:
>
>	
>	ofstream fout("myFile");
>	.
>	.
>	.
>	myObject.WriteYourInfo(fout);
>	.
>	.
>	.
>	fout.close()
>
>	It works perfectly under MS-DOS, compiling with DJGPP. Under Linux the
>output goes to stdout instead of going to the file. Both versions of gcc
>are 2.7.2.
>	What am I doing wrong? HELP!!!

Does fout get opened properly?  Perhaps it doesn't and hence something
funky is happening?

- Greg
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