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Date: Thu, 14 Feb 2002 12:21:38 +0200 (IST)
From: Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
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To: Tim Van Holder <tim DOT van DOT holder AT pandora DOT be>
cc: djgpp-workers AT delorie DOT com
Subject: Re: Some small bash issues
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On 14 Feb 2002, Tim Van Holder wrote:

>    foo=bar ./shell-script
> 
> because everything in the script is simply a 'new command'.

I fail to see the difference between

     foo=bar ./script
and
     foo=bar echo $foo

What is the difference here?

>   foo=bar ./perl-script
> 
> works fine (presumably, bash tries to process it as a shell script, sees
> the #!, expands the envvar, and hands the script off to the system).
> On DJGPP, bash runs the script without substituting the variable.

Why doesn't Bash expand the variable in the DJGPP port?