Date: Thu, 2 Mar 2000 11:09:24 +0200 (IST)
From: Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
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To: Mariano Alvarez =?iso-8859-1?Q?Fern=E1ndez?= <malfer AT teleline DOT es>
cc: "djgpp-workers AT delorie DOT com" <djgpp-workers AT Delorie DOT com>
Subject: Re: short file names when using LFN
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On Wed, 1 Mar 2000, Mariano Alvarez =?iso-8859-1?Q?Fern=E1ndez?= wrote:

> >      putenv ("LFN=n");
> >      _truename (long_name, short_name);
> >      putenv ("LFN=y");
> 
> No, sorry, this don't work to get the real sfn of a file.

Please post the details.  The short test program attached below works
for me.

> > > Now, I only need the put routine :-) I'm playing with a crazy idea:
> > > do the copy, compare the short filenames
> > > if they don't match rename the copied file adding .00n
> > > do another copy and try again
> > > when the short filenames match, delete the bad copies.
>
> > I don't understand what are you trying to accomplish.  Please
> > explain.
> 
> I mailed about this to the general list, I want a copy utility who take care
> about sfn and lfn of each file.

This is AFAIK impossible.  But I still don't think I understand why do
you think your idea should work.  Are you assuming that Windows
eventually runs out of the numeric tails and begins to reuse them?


#include <sys/stat.h>
#include <stdlib.h>
#include <stdio.h>

int main (int argc, char *argv[])
{
  char short_name[FILENAME_MAX];
  const char *long_name = argc > 1 ? argv[1] : argv[0];

  putenv ("LFN=n");
  _truename (long_name, short_name);
  putenv ("LFN=y");
  printf ("`%s' -> `%s'\n", long_name, short_name);
  return 0;
}