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Subject: Re: printf() doesn't print long long intege, maybe RHIDE problem
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greenberg moshe wrote:
> Hi
> printf() do not print long long integer.
> It look like RHIDE problem because the size check of the number is ok.
> Moshe 
> 
> 
Show us how it fails.  Here is an example of it working:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <string.h>

int main(void)
{
     long long xll;
     size_t i, j, ndx, n = sizeof(long long) / sizeof(int);
     int x[n];
     char c[sizeof(long long)];
     if (sizeof(long long) % sizeof(int)) {
         printf
             ("This example requires sizeof(long long) to be\n"
              "  a multiple of sizeof(int)\n");
         exit(EXIT_FAILURE);
     }
     srand(time(0));
     for (i = 0; i < 5; i++) {
         for (ndx = 0, j = 0; j < n; j++, ndx += sizeof(int)) {
             x[j] = rand();
             memcpy(c + ndx, x + j, sizeof(int));
         }
         memcpy(&xll, c, sizeof(long long));
         printf("Here is a long long: %lld (decimal) %#llx (hex)\n"
                "made from these ints (as hex):\n",
                xll, (unsigned long long) xll);
         for (j = 0; j < n; j++)
             printf("%#x ", (unsigned) x[j]);
         printf("\n\n");
     }
     return 0;
}



Here is a long long: 5983791420887767295 (decimal) 0x530ab298040b98ff (hex)
made from these ints (as hex):
0x40b98ff 0x530ab298

Here is a long long: 9081887572752223580 (decimal) 0x7e0958a127ee4d5c (hex)
made from these ints (as hex):
0x27ee4d5c 0x7e0958a1

Here is a long long: 199024756084199939 (decimal) 0x2c313f60fe85203 (hex)
made from these ints (as hex):
0xfe85203 0x2c313f6

Here is a long long: 7037913556498271489 (decimal) 0x61abb11756fc4d01 (hex)
made from these ints (as hex):
0x56fc4d01 0x61abb117

Here is a long long: 1917151184894115895 (decimal) 0x1a9b16d85c554037 (hex)
made from these ints (as hex):
0x5c554037 0x1a9b16d8