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From: Martin Ambuhl <mambuhl AT earthlink DOT net>
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Subject: Re: Does using '-std=c99' with gcc 3.3.x cause '__STRICT_ANSI__'
 to be defined?
References: <btarqo$kgr$1 AT au-nws-0001 DOT flow DOT com DOT au>
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Date: Mon, 05 Jan 2004 08:45:01 GMT
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bdeck wrote:
<nothing>

Please do not hide questions in the subject line.
This one you could answer for yourself:

#include <stdio.h>

int main(void)
{
	printf("[Output]\n");
#if defined(__STRICT_ANSI__)
	printf("__STRICT_ANSI__ defined\n");
#else
	printf("__STRICT_ANSI__ not defined\n");
#endif
	return 0;
}

gcc -O2 -W -Wall -Wwrite-strings -std=c99 -pedantic a.c 2>a.e
./a
[Output]
__STRICT_ANSI__ defined

gcc -std=c99 -pedantic a.c 2>a.e
./a
[Output]
__STRICT_ANSI__ defined


-- 
Martin Ambuhl