Message-ID: <3B4536ED.EAC586B2@alpha.delta.edu> Date: Thu, 05 Jul 2001 23:56:29 -0400 From: "David Witbrodt" X-Mailer: Mozilla 4.75 [en] (Win98; U) X-Accept-Language: en,ja MIME-Version: 1.0 To: djgpp AT delorie DOT com Subject: Re: Thanks for statfs() rev. 1.6! References: <200107050333 DOT FAA14607 AT father DOT ludd DOT luth DOT se> Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Reply-To: djgpp AT delorie DOT com Martin Str|mberg wrote: > > I would like to thank the DJGPP-workers and N. A. Bensa for their > > attempt to get statfs() [rev. 1.6 on CVS] to read the correct drive > > space information. It works -- with a slight discrepancy (less than > > 2% on my machine), but it's good enough for my current purposes. > > As the intent was to have no discrepancies, I'd like to know more. > What does statfs() say and how do you verify that? By "discrepancy" I meant only that Windows 98 and statfs() do not report the same amount of free space left on my hard drive's partition. Info source Free bytes reported =========== =================== C:->Properties 4 095 901 696 bytes Scandisk 4 095 901 696 bytes statfs() 4 026 531 840 bytes The discrepancy is 69 369 856 bytes, and I don't claim to have a clue as to which figure is correct. Maybe neither. I assume they're both in the ballpark, and that is more or less all I am looking for. Perfection would be nice, and if I had a machine of my own I might do some research and experimentation to try to find out what is going on. I should have a machine of my own in August, so maybe then.... Thanks again, Dave W.