Message-ID: <38FE9B26.A0D244EE@unb.ca>
From: Endlisnis <s257m AT unb DOT ca>
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Subject: Re: inefficiency of GCC output code & -O problem
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Date: Thu, 20 Apr 2000 05:50:43 GMT
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

"Alexei A. Frounze" wrote:

> > >> >      };
> > >>         ^
> > >> Why this semicolon? The same thing I see everywhere in your sources.
> > >
> > >Do you think this semicolon makes something slower?
> >
> > No. But why the semicolon. It seems highly unconventional to me.
>
> But not for me. Let me explain it... First programming language that I've learnt
> is Pascal (I don't say about Basic, because IMHO it's not a PL, it's something
> for beginners and dummies :). In Pascal composite operators are made this way:
>
> BEGIN
>   operator1;
>   operator2;
> END;
>    ^ this semicolon must be present always.

But, in C, if you try:

if(expr) {
  func();
  func();
  };  /* <--- */
else
  func();

You will get a parse error.

--
     (\/) Endlisnis (\/)
          s257m AT unb DOT ca
          Endlisnis AT HotMail DOT com
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