From: Hans-Bernhard Broeker <broeker AT acp3bf DOT physik DOT rwth-aachen DOT de>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Weird output of printf()
Date: 25 Jan 2000 09:28:12 GMT
Organization: Aachen University of Technology (RWTH)
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To: djgpp AT delorie DOT com
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Jason Green <news AT jgreen4 DOT fsnet DOT co DOT uk> wrote:
> Eli Zaretskii <eliz AT is DOT elta DOT co DOT il> wrote:

>> If you want the leading zero, use "%#0x" as your format specifier.  

> This does not work (although I don't know that it should.)

> Apparent behaviour of printf is to ignore the 0 flag and the width
> field whenever the # flag is used.

Not really, I think. You're just a tid bit off in your format spec,
preventing it from doing what you want:

> If it should work then I would expect "%#02x" to be the required

Make that "%#04x", and it'll work. The '2' is too small, as it has to
count total output field width, including the "0x" added by that '#'
option in the format.

------ shell excerpt --------
E:\>type tt.c
#include <stdio.h>

int main(void) {
  printf("%#04x\n", 0x0f);
  return 0;
}

E:\>tt
0x0f
------- end ----------------

Alternatively, you could 

	printf("0x%02x\n", 0x0f);

Same result, easier to understand.
-- 
Hans-Bernhard Broeker (broeker AT physik DOT rwth-aachen DOT de)
Even if all the snow were burnt, ashes would remain.