From: Jason Green <news AT jgreen4 DOT fsnet DOT co DOT uk>
Newsgroups: comp.os.msdos.djgpp
Subject: Re: Weird output of printf()
Date: Sun, 23 Jan 2000 21:16:15 +0000
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David Cleaver <davidis AT ou DOT edu> wrote:

> Well, if you really want to know the print line I'm using is:

It is not a case of wanting to know.  Damian needed more information
because he wanted to help you.

> Anyway,  does the compiler actually think that 0xf is the same as 0x0f? 

Yes, 0xf *is* the same as 0x0f (and so are 0x0000000F and 15 and 017).

> Ok, If I have four char's {0x0f, 0x0f, 0x01, 0x07}
> and I want to convert it to an int I just combine them all into:
> {0x0f0f0107} right?
> Please tell me if this is correct.

Yes and No.  It is correct for what you want to do, but there are some
situations where the byte order is important.

> So, would the compiler be able to recognize if I chaged the array:
> from {0xf, 0xf, 0x1, 0x7} to {0xff17}?
> 
> I don't think so. So, I would like for printf (or fprintf) to print out
> the leading zero so I don't have to go back and add all of them.  Any
> help that you can give will be appreciated very much.

How about printing the whole 32-bit value with something like this:

fprintf(out, "0x%02x%02x%02x%02x", 
                array0[looper1][looper2],
                array0[looper1][looper2+1],
                array0[looper1][looper2+2],
                array0[looper1][looper2+3]);

C language questions like this (and some others you've asked) would be
better put in groups such as alt.comp.lang.learn.c-c++ and comp.lang.c