From: "Damian Yerrick" <NOSP AT Musenet@pineight.8m.com>
Newsgroups: comp.os.msdos.djgpp
References: <82cko6$sfk$1 AT imsp026 DOT netvigator DOT com>
Subject: Re: Why "c" is always zero??
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NNTP-Posting-Date: Sun, 05 Dec 1999 05:59:32 GMT
Distribution: world
Date: Sun, 05 Dec 1999 05:59:32 GMT
To: djgpp AT delorie DOT com
DJ-Gateway: from newsgroup comp.os.msdos.djgpp
Reply-To: djgpp AT delorie DOT com


"Jason Yip" <manman AT netteens DOT net> wrote in message
news:82cko6$sfk$1 AT imsp026 DOT netvigator DOT com...
>Can anyone tells me why the value of "c" is always equal to zero??
>How can I correct this?
>Thanks a lot!!

>#include <stdio.h>
>float ftc(n)
>int n;

For one thing you're using old-style K&R function defs.

float ftc(int n)

>{
>float c, f; int i;

Where do you assign the local variable 'f' a value?

> for (i=0;i<=n;i++){
> c=5/9*(f-32);
>        }
>return c;
>}

>main ()
int main()
>{
>float c, f=0; int i=0;
>do
>{
>c=ftc(i);
>printf("\t\t F=%.2f \t\t C=%.2f\n",f,c);
>f++;
>i++;
>} while (i<=100);
>}


try this

#include <stdio.h>
float fahren2celsius(float fahren)
{
  return 5/9 * (fahren - 32.);
}

int main()
{
  int i;
  float fahren, celsius;

  for(i = 0; i < 212; i++)
  {
    fahren = i;
    celsius = fahren2celsius(fahren);
    printf("%f deg F = %f deg C\n", fahren, celsius);
  }

  return 0;
}


--
Damian Yerrick
http://yerricde.tripod.com/
My .sig is too long to include in an e-mail or NG message.
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