Message-ID: <37B19BD6.50E5@ns.sympatico.ca>
From: Klaas <klaas1 AT ns DOT sympatico DOT ca>
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Newsgroups: comp.os.msdos.djgpp
Subject: Re: uclock() and Integer
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Date: Wed, 11 Aug 1999 12:50:46 -0300
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To: djgpp AT delorie DOT com
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Reply-To: djgpp AT delorie DOT com

Thiago F.G. Albuquerque wrote:
> 
> Quoting libc's documentation,
> 
> "(...) `printf' cannot print a value of type `uclock_t', even though
> it is an integer value, because it is a 64-bit integer."
> 
> So I thought of using libg++'s Integer class to print this 64-bit integer
> and wrote this piece of code:
> 
> #include <allegro.h>
> #include <time.h>
> #include <stdio.h>
> #include <integer.h>
> 
> int main()
> {
>  allegro_init();
>  install_keyboard();
> 
>  uclock();
>  Integer i;
> 
>  while(!key[KEY_ESC])
>  {
>   i = uclock();
>   cout << i << endl;
>  }
> 
>  return 0;
> }
> 
> However, the first lines of output were:
> 
> 25
> 2317
> 4860
> 7466
> 10050
> 12645
> 15236
> -47579
> -45450
> -42852
> -40260
> -37660
> -35064
> -32469
> -30044
> -27873
> -25200
> -22602
> 
> Why is it printing negative values?
> 
> Do you know another way of printing an uclock_t?
> 
> ----------------------------
> Thiago

The value of a 64bit integer can be up to 1.84E19.

When you transpose this onto an int (though it seems as though you are
using a short) the top gets chopped off, and it can also set the "-" bit
of the variable.

A "long long unsigned" should be able to hold 64bits...

-Mike