From: Erik Max Francis Newsgroups: comp.os.msdos.djgpp Subject: Re: working out circumference help Date: Mon, 01 Sep 1997 13:16:46 -0700 Organization: Alcyone Systems Lines: 49 Message-ID: <340B22AE.561D08E0@alcyone.com> References: <01bcb6e0$041efb00$LocalHost AT rossa> NNTP-Posting-Host: newton.alcyone.com Mime-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit To: djgpp AT delorie DOT com DJ-Gateway: from newsgroup comp.os.msdos.djgpp Precedence: bulk Ross Boast wrote: > Yep its me again and once again i need help (with djgpp that > is:). Your problems are actually not specific to C. They are standard C questions. > int a,b; Since you ultimately want to print a floating point value, you should declare a and b as double. > scanf("%i", &a); To make this work with doubles, you'd have to use scanf("%lf", &a); > b = (a,2) * PI; This isn't the way to do multiplication. You mean: b = 2*a*PI; > printf ("The circumference of the circle is %i\n\n"); There is no argument passed to printf to correspond to the format specifier here. In any case, since you should be using floating point, the format should be %f: printf("The circumference of the circle is %f\n", b); Note that the format specifiers _are_ different for printf and scanf. %f is a float in scanf, %lf is a double in scanf. In printf, variable arguments are automatically promoted, so %f is for both float and double. > Thanks in advance. My advice to you is to get a good book on ANSI C and read up some more. -- Erik Max Francis, &tSftDotIotE / mailto:max AT alcyone DOT com Alcyone Systems / http://www.alcyone.com/max/ San Jose, California, United States / icbm://37.20.07n/121.53.38w \ "War is like love; / it always finds a way." / Bertolt Brecht