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Date: Sat, 8 Nov 2025 21:01:56 +0900
To: cygwin AT cygwin DOT com
Subject: [gcc] Bug in emutls?
Message-Id: <20251108210156.20eadc80a8161eece6810175@nifty.ne.jp>
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From: Takashi Yano via Cygwin <cygwin AT cygwin DOT com>
Reply-To: Takashi Yano <takashi DOT yano AT nifty DOT ne DOT jp>
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Hi everyone,

I encountered a problem with static thread_local in C++ program.
The following simple reproducer does not work as expected if it
runs under cygwin 3.7.0 (Test), while it works under cygwin 3.6.5.

To conclude, this was not a bug in Cygwin 3.7.0.

This is triggered by the commit:
commit ebd92b128f62a0b3c270319487b8486abdfa405b
Author: Takashi Yano <takashi DOT yano AT nifty DOT ne DOT jp>
Date:   Fri Apr 4 21:22:27 2025 +0900

    Cygwin: thread: Use simple array instead of List<pthread_key>

where the call order of the destructors for pthread_key was changed.
The call order can depend on implementation. So the code using
pthread_key should not expect any predetermined call order of the
destuctors.

The result of the following code is
1: 0xa00016938
2: 0xa00016b98
X::print(): 2
X::print(): 1
X::~X(): 1
X::~X(): 2
under cygwin 3.6.5, while it is
1: 0xa00016938
2: 0xa00016b98
X::print(): 2
X::print(): 1
X::~X(): 2133815816
X::~X(): 2133815816
under cygwin 3.7.0 (Test).

I looked into the problem, and found that the executable for
the following code registers two pthread_keys with each destructor;
one is void emutls_destroy(void *ptr) in libgcc/emutls.c, and the
other is void run(void *p) in libstdc++-v3/libsupc++/atexit_thread.cc.
emutls_destroy() free's the memory erea of static thread_local X,
that is accessed from X::~X() which is called from run(). As a result,
if the emutls_destroy() is called before run(), run() referres to
the memory erea already free'ed.

I think this is a bug of gcc. This issue does not occur in Linux,
because Linux does not use emutls.

Any idea?


#include <thread>
#include <cstdio>
#include <unistd.h>

class X {
	int n;
public:
	X(int n1) : n(n1) {}
	~X() {
		printf("X::~X(): %d\n", n);
	}
	void print() {
		printf("X::print(): %d\n", n);
	}
};

void func(int n) {
	static thread_local X x(n);
	printf("%d: %p\n", n, &x);
	usleep(10000);
	x.print();
	usleep(10000);
}

int main() {
	std::thread t1(func, 1);
	std::thread t2(func, 2);

	t1.join();
	t2.join();

	return 0;
}

Any idea?

-- 
Takashi Yano <takashi DOT yano AT nifty DOT ne DOT jp>

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