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Date: Mon, 7 Oct 2019 22:51:35 +0200 (CEST)
From: "donpedro.tdcadsl.dk via cygwin" <cygwin AT cygwin DOT com>
Reply-To: donpedro AT tdcadsl DOT dk
To: cygwin AT cygwin DOT com
Cc: pdtychsen DOT ext AT gn DOT com
Message-ID: <1549599310.1980812.1570481495155.JavaMail.zimbra@tdcadsl.dk>
Subject: execvp* and spawnvp* react differently to same PATH environment variable
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Hi all, 

While working on something i noticed that execvp* and spawnvp* behave differently with regards to $PATH, which i think is not correct. 

----------------------------------------------

1) The execvp* functions are called like this: 

return spawnve ( _P_OVERLAY | _P_PATH_TYPE_EXEC , 
   find_exec ( file , buf , "PATH" , FE_NNF ) ? : "" , 
   argv , envp );

This calls find_exec() with FE_NNF, which causes the path to be NULL if not found in $PATH.

This later causes cygwin to fail correctly if the program is not in $PATH.

----------------------------------------------

2) The spawnvp* functions are called like this: 

return spawnve (mode | _P_PATH_TYPE_EXEC, find_exec (file, buf), argv, cur_environ ());

This does _not_ calls find_exec() with FE_NNF which causes the path to be the posix form, as it is not found in path.

This later causes cygwin to find the program even though it was not in $PATH which seems wrong.

----------------------------------------------

This seems like a bug in spawnvp* functions unless i am missing something? 

Any thoughts?

Thanks,

/pedro


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