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Date: Wed, 08 Oct 2014 08:24:33 -0600
From: Eric Blake <eblake AT redhat DOT com>
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To: cygwin AT cygwin DOT com
Subject: Re: Question regarding grep 2,6,3 regular expression looking for lines without something in a part of a line
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On 10/08/2014 08:00 AM, Larry W. Virden wrote:
> I am using an older version of cygwin on a Windows 7 PC.
> I have a file of data that is formatted in character separated value form=
at.
> For example, a couple of lines might be:
>=20
> "Doe, John";"Student";"Senior"
> "Admin";"Staff";
>=20
> Now, I want to perform a grep that returns lines that do not have a
> comma in the "first column" of data.
>=20
> I tried the obvious
> grep '^"[^,"]";' file.csv

That looks for lines containing a literal quote, then exactly one quoted
character that is neither comma nor quote, then another literal quote.
You forgot the *:

'^"[^,"]*";'

Your question is not cygwin-specific.

--=20
Eric Blake   eblake redhat com    +1-919-301-3266
Libvirt virtualization library http://libvirt.org


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