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Date: Mon, 10 Mar 2014 10:11:05 +0100
Message-ID: <CAKw7uVjEEPzo4LxdSckNjEsgjbN22Wn=-Fe3+tao5GkbwvCamQ@mail.gmail.com>
Subject: Re: strtold() availability
From: =?UTF-8?Q?V=C3=A1clav_Zeman?= <vhaisman AT gmail DOT com>
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On 7 March 2014 21:08, Corinna Vinschen wrote:
> On Mar  7 17:04, Václav Zeman wrote:
>> Hi.
>>
>> This bit from /usr/include/stdlib.h hides the `strtold()` function
>> even though the `strtold` symbol appears to be exported from
>> `cygwin1.dll`:
>>
>> ~~~~{.c}
>> /* On platforms where long double equals double.  */
>> #ifdef _LDBL_EQ_DBL
>> #if !defined(__STRICT_ANSI__) || (__STDC_VERSION__ >= 199901L) ||
>> (__cplusplus >= 201103L)
>> extern long double strtold (const char *__restrict, char **__restrict);
>> #endif
>> #endif /* _LDBL_EQ_DBL */
>> ~~~~
>>
>> This in turn breaks my source because I cannot use `_GLIBCXX_USE_C99`
>> to expose some C++11 features like `std::vsnprintf()`.
>>
>> Shouldn't the `_LDBL_EQ_DBL` guard be removed and the function exposed
>> regardless of `double` and `long double` sizes?
>
> I fixed that in newlib after a discussion with my co-maintainer.
> strtold now gets defined if _HAVE_LONG_DOUBLE is defined.  This is
> the case for Cygwin, for instance.

I think that similar fix needs to be applied to `wchar.h` and `wcstold()`.

-- 
VZ

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