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Date: Sun, 13 Jan 2013 21:11:44 -0800 (PST)
From: YZFury <yzfury AT gmail DOT com>
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Subject: Re: Using the free(*ptr) routine and getting an exception, "Exception: STATUS_ACCESS_VIOLATION"
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Whoops.   I was making the pointer point to x instead of putting x's value in the memory that was just allocated.   Now i understand that. Really sorry for a stupid syntax error question on my part. thanks for the quick reply though :).  Like I said basically new to C. 

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_____________________________________________
From: "Dan Kegel-2 [via Cygwin]" <ml-node+s1069669n95381h52 AT n5 DOT nabble DOT com>
Sent: Sun Jan 13 23:52:50 EST 2013
To: YZFury <yzfury AT gmail DOT com>
Subject: Re: Using the free(*ptr) routine and getting an exception, "Exception: STATUS_ACCESS_VIOLATION"


	On Sun, Jan 13, 2013 at 7:55 PM, YZFury <[hidden email]> wrote: 
> int *ptr = malloc(sizeof(*ptr)); 
>         int x = 87; 
>         ptr = &x; 
>         printf("%d", *ptr); 
>         free(ptr);//it goes wrong here 

As you probably know, you can't call free() on a pointer 
that didn't come from malloc().  ptr's first value came from malloc, 
but you overwrote that with 
   ptr = &x; 
Perhaps you meant 
   *ptr = x; 
So you're a level of indirection off. 
- Dan 

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