Message-ID: <45A6D6FE.7030406@gmail.com>
Date: Thu, 11 Jan 2007 17:31:58 -0700
From: Morgan Gangwere <0 DOT fractalus AT gmail DOT com>
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To: cygwin AT cygwin DOT com
Subject: Re: command line arg expansion
References: <001301c735b8$0bf0bf10$300b17ac AT sanmateo DOT corp DOT akamai DOT com>
In-Reply-To: <001301c735b8$0bf0bf10$300b17ac@sanmateo.corp.akamai.com>
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jim wrote:
> I have recently upgraded from 1.5.12 to 1.5.23 and noticed something that
> has me wondering.    I compiled this on 1.5.23 and have run it under cmd.exe
> on on 1.5.12 and 1.5.23:
> 
> #include <stdio.h>
> 
> int main(int argc, char *argv[])
> {
>    int i, c;
> 
>    for (i = 0; i < argc; i++)
>       printf("arg[%d]: '%s'\n", i, argv[i]);
> }
> 
> On 1.5.12:
> C:\>e '/.*/'
> arg[0]: 'e'
> arg[1]: '/.*/'
> 
> On 1.5.23:
> C:\>e '/.*/'
> arg[0]: 'e'
> arg[1]: '/../'
> arg[2]: '/./'
> arg[3]: '/.other/'
> 
> It appears that the runtime initialization on 1.5.23 is doing command line
> expansion - is this correct?   If so, is this change documented somewhere so
> I get the full explanation?
> 
> thanks for any insight,
> jim
> 
> 
> 
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> 
isnt this because if the wildcard reading in 1.5.23?

i have seen this several times, especially in this kind of program.
handle the argv[] as an array of real strings and
 you should be fine TTBOMK
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