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Date: Thu, 12 May 2005 20:39:33 +1000
From: Erik de Castro Lopo <cygwin-erikd AT mega-nerd DOT com>
To: cygwin AT cygwin DOT com
Subject: Re: gcc + cygwin
Message-Id: <20050512203933.1d4723cc.cygwin-erikd@mega-nerd.com>
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References: <20050512095949 DOT 87139 DOT qmail AT web50810 DOT mail DOT yahoo DOT com>
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Marcel wrote:

> I've been using a particular set of C-code for years
> on several systems (mostly linux on PC, or Unix on
> some Sun) and could always get it to work when I moved
> to a new machine.
> 
> Now, I'm trying to get it to work on a PC with cygwin.
> 
> cygcheck claims I have gcc version 3.3.3-3 OK.
> 
> I am NOT an experienced C or cygwin user, but the
> problems I keep running into, appear to me that gcc
> with cygwin behaves very differently from whatever I
> had on the previous systems.
> 
> gcc -g -Wall -c flm.c
> flm.c:37: error: initializer element is not constant
> make: *** [flm.o] Error 1
> 
> The offending line.37 was:
> FILE *ch_par=stdout,*ch_verify=NULL;
> 
> In my ignorance, I have to assume that gcc/cygwin is
> not compatible with other gcc implementations. Can
> that
> be? Or could I have a botched installation of
> cygwin+gcc?

Probably neither.

I think the C standard says that stdout might not be a compile
time constant.

The fix to this is th change line 37 to:

    FILE *ch_par = NULL, *ch_verify = NULL;

Then, in the first function that uses ch_par, set it to stdout.
If this file has a main() function you can just do this at the
start of main:

    ch_par = stdout;

if the file doesn't contain a main() function you should probably 
do this in each function that uses ch_par:

   if (ch_par == NULL)
        ch_par = stdout ;

Hope this helps,
Erik
-- 
+-----------------------------------------------------------+
  Erik de Castro Lopo  nospam AT mega-nerd DOT com (Yes it's valid)
+-----------------------------------------------------------+
"When your hammer is C++, everything begins to look like a thumb."
-- Steve Haflich, in comp.lang.c++

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