Mailing-List: contact cygwin-help AT cygwin DOT com; run by ezmlm List-Subscribe: List-Archive: List-Post: List-Help: , Sender: cygwin-owner AT cygwin DOT com Mail-Followup-To: cygwin AT cygwin DOT com Delivered-To: mailing list cygwin AT cygwin DOT com Message-ID: <20020610081621.48913.qmail@web10408.mail.yahoo.com> Date: Mon, 10 Jun 2002 01:16:21 -0700 (PDT) From: Suman Kumar Ray Subject: performance question To: cygwin AT cygwin DOT com MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Hello, I have observed that if I run any program linked with cygwin1.dll (1003.10.0.0) from windows command prompt, it takes longer time to execute than if I run the same under cygwin bash shell. I have tested it with gcc -v command. I initialy thought it is because, every time I run the program from windows cmd shell, cygwin1.dll creates and initializes the shared region, so it takes more time. Then I first launch bash shell assuming its invocation will create the shared region. Then I launch windows command shell, (i.e. so now both bash and windows command shell exists at same time). Still performance of "gcc -v" from windows command shell is slower than running "gcc -v" within bash. I am using dell laptop ,windows 2000, pentium III with 256 MB RAM. Can anyone tell me any reason for this slowness, and how can I get the same performance as I get from bash shell for any program linked with cygwin1.dll ? Thanks, Suman Ray __________________________________________________ Do You Yahoo!? Yahoo! - Official partner of 2002 FIFA World Cup http://fifaworldcup.yahoo.com -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Bug reporting: http://cygwin.com/bugs.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/