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Message-ID: <657B20E93E93D4118F9700D0B73CE3EA0D397198@goofy.epylon.lan>
From: Sanjay Gupta <SGupta AT Epylon DOT com>
To: "'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com>
Subject: Path Name Help
Date: Thu, 28 Feb 2002 12:34:37 -0800
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OS : Win NT 4.0 SP 6a

I am writing shell script which does Oracle Export. In the script, I have to
give the name of export file, I am not sure how to include the path
information.

Example :-

exp system/manager file=/usr/exp.dmp  full=Y

see the file= parameter, when I use the above command then the Oracle exp
utility is not able to recognize the file information, it gives error
"failed to open /usr/exp.dmp for write"
So looks like unix style path does not work.

Then I tried window style path

exp system/manager file=d:\Oracle8i\Exp\Exp.dmp  full=Y

This works but it does not create file in d:\Oracle8i\Exp directory but in
creates file in D root directory i.e. in D:\ with name  oracle8iexpexp.dmp.
So this also does not create file in appropiate directory.

Please help me.

Thanks in Advance.



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